Ionisation energy, electron gain energy and electronegativity

Unit 1 · Atomic Structure

First and successive ionisation energies and the factors that control them, the trends and dips across periods 2 and 3, electron gain energy, and Pauling electronegativity and its trends.

First ionisation energy

The first ionisation energy ($IE_1$) of an element is the minimum energy needed to remove the most loosely held electron from each atom in one mole of gaseous atoms in their ground state, forming one mole of gaseous unipositive ions: $$\text{X(g)} \rightarrow \text{X}^+\text{(g)} + e^- \qquad \Delta H = IE_1$$ Energy must always be supplied to pull an electron away from the nucleus, so ionisation energies are positive (endothermic). For sodium, $IE_1 = 496\ \text{kJ mol}^{-1}$. The atoms must be gaseous, so that no energy is needed to separate them from each other.

Four factors decide how hard it is to remove an electron:

Trends in the first ionisation energy

First ionisation energies

Element H He Li Be B C N O F Ne
$IE_1$ / kJ mol⁻¹ 1312 2372 520 899 801 1086 1402 1314 1681 2081
Element Na Mg Al Si P S Cl Ar K Ca
$IE_1$ / kJ mol⁻¹ 496 738 578 787 1012 1000 1251 1521 419 590

Across a period $IE_1$ increases in general, because the nuclear charge rises while the electrons are removed from the same shell with little extra shielding, so the atoms get smaller and hold their electrons more tightly. The noble gas at the end of each period has the highest value; helium has the highest of all.

Down a group $IE_1$ decreases (Li 520, Na 496, K 419): the outer electron is in a higher shell, further from the nucleus and better shielded. The increase in nuclear charge is outweighed.

There are two small drops in each of periods 2 and 3:

The large drop from a noble gas to the next alkali metal (Ne 2081 → Na 496) is because the next electron starts a new shell.

Successive ionisation energies

The second ionisation energy is the energy for $\text{X}^+\text{(g)} \rightarrow \text{X}^{2+}\text{(g)} + e^-$, and so on. Successive ionisation energies always increase: each electron is pulled away from an ion that is more positive. The increases are gradual while electrons come from the same shell, and there is a very large jump when the next electron must be taken from an inner shell, closer to the nucleus and less shielded.

Successive ionisation energies of aluminium

For aluminium ($1s^2,2s^2,2p^6,3s^2,3p^1$) the jump comes after the third electron ($IE_3 = 2745$, $IE_4 = 11,577\ \text{kJ mol}^{-1}$): aluminium has three outer electrons and is in group 13. A second huge jump after the 11th electron marks the move into the $n = 1$ shell. Successive ionisation energies were among the first evidence for shells.

Example: The first four ionisation energies of an element are 738, 1451, 7733 and 10 540 $\text{kJ mol}^{-1}$. The big jump is between $IE_2$ and $IE_3$, so the element has two outer electrons: it is in group 2 (it is magnesium), and it forms $\text{X}^{2+}$ ions.

Electron gain energy

The first electron gain energy (electron affinity) is the energy change when one mole of gaseous atoms each gain one electron to form one mole of gaseous uninegative ions: $$\text{X(g)} + e^- \rightarrow \text{X}^-\text{(g)}$$ For most non-metals energy is released (the value is negative), because the added electron is attracted by the nucleus.

Atom F Cl Br I O S N C
electron gain energy / kJ mol⁻¹ −328 −349 −325 −295 −141 −200 ≈ +7 −122

Electronegativity

Electronegativity is the ability of an atom in a covalent bond to attract the shared pair of electrons towards itself. It is not measured directly; Linus Pauling's scale gives fluorine the highest value.

Pauling electronegativities

The difference in electronegativity between two bonded atoms decides how polar the bond is: equal values give a non-polar covalent bond, a small difference a polar covalent bond, and a large difference (roughly above 2) an essentially ionic bond. Unit 2 builds on this.

Property Across a period (left → right) Down a group
atomic radius decreases increases
first ionisation energy increases (with dips) decreases
electronegativity increases decreases
metallic character decreases increases

Exam tip: When asked to explain an ionisation energy trend, name the factors (nuclear charge, distance, shielding) and say which one wins. For the dips, quote the electron configurations (B: $2s^2,2p^1$; O: $2s^2,2p^4$ with one paired 2p orbital). Remember the definitions need gaseous atoms and one mole.